{-# LANGUAGE DeriveFunctor #-} {-# LANGUAGE DeriveTraversable #-} {-# LANGUAGE DeriveFoldable #-} -- | See module Distribution.Backpack.ModuleScope ( -- * Module scopes ModuleScope(..), ModuleProvides, ModuleRequires, ModuleSource(..), dispModuleSource, WithSource(..), unWithSource, getSource, ModuleWithSource, emptyModuleScope, ) where import Prelude () import Distribution.Compat.Prelude import Distribution.ModuleName import Distribution.Types.IncludeRenaming import Distribution.Types.PackageName import Distribution.Types.ComponentName import Distribution.Backpack import Distribution.Backpack.ModSubst import Distribution.Text import qualified Data.Map as Map import Text.PrettyPrint ----------------------------------------------------------------------- -- Module scopes -- Why is ModuleProvides so complicated? The basic problem is that -- we want to support this: -- -- package p where -- include q (A) -- include r (A) -- module B where -- import "q" A -- import "r" A -- -- Specifically, in Cabal today it is NOT an error have two modules in -- scope with the same identifier. So we need to preserve this for -- Backpack. The modification is that an ambiguous module name is -- OK... as long as it is NOT used to fill a requirement! -- -- So as a first try, we might try deferring unifying provisions that -- are being glommed together, and check for equality after the fact. -- But this doesn't work, because what if a multi-module provision -- is used to fill a requirement?! So you do the equality test -- IMMEDIATELY before a requirement fill happens... or never at all. -- -- Alternate strategy: go ahead and unify, and then if it is revealed -- that some requirements got filled "out-of-thin-air", error. -- | A 'ModuleScope' describes the modules and requirements that -- are in-scope as we are processing a Cabal package. Unlike -- a 'ModuleShape', there may be multiple modules in scope at -- the same 'ModuleName'; this is only an error if we attempt -- to use those modules to fill a requirement. A 'ModuleScope' -- can influence the 'ModuleShape' via a reexport. data ModuleScope = ModuleScope { modScopeProvides :: ModuleProvides, modScopeRequires :: ModuleRequires } -- | An empty 'ModuleScope'. emptyModuleScope :: ModuleScope emptyModuleScope = ModuleScope Map.empty Map.empty -- | Every 'Module' in scope at a 'ModuleName' is annotated with -- the 'PackageName' it comes from. type ModuleProvides = Map ModuleName [ModuleWithSource] -- | INVARIANT: entries for ModuleName m, have msrc_module is OpenModuleVar m type ModuleRequires = Map ModuleName [ModuleWithSource] -- TODO: consider newtping the two types above. -- | Description of where a module participating in mixin linking came -- from. data ModuleSource = FromMixins PackageName ComponentName IncludeRenaming | FromBuildDepends PackageName ComponentName | FromExposedModules ModuleName | FromOtherModules ModuleName | FromSignatures ModuleName -- We don't have line numbers, but if we did, we'd want to record that -- too -- TODO: Deduplicate this with Distribution.Backpack.UnifyM.ci_msg dispModuleSource :: ModuleSource -> Doc dispModuleSource (FromMixins pn cn incls) = text "mixins:" <+> dispComponent pn cn <+> disp incls dispModuleSource (FromBuildDepends pn cn) = text "build-depends:" <+> dispComponent pn cn dispModuleSource (FromExposedModules m) = text "exposed-modules:" <+> disp m dispModuleSource (FromOtherModules m) = text "other-modules:" <+> disp m dispModuleSource (FromSignatures m) = text "signatures:" <+> disp m -- Dependency dispComponent :: PackageName -> ComponentName -> Doc dispComponent pn cn = -- NB: This syntax isn't quite the source syntax, but it -- should be clear enough. To do source syntax, we'd -- need to know what the package we're linking is. case cn of CLibName -> disp pn CSubLibName ucn -> disp pn <<>> colon <<>> disp ucn -- Case below shouldn't happen _ -> disp pn <+> parens (disp cn) -- | An 'OpenModule', annotated with where it came from in a Cabal file. data WithSource a = WithSource ModuleSource a deriving (Functor, Foldable, Traversable) unWithSource :: WithSource a -> a unWithSource (WithSource _ x) = x getSource :: WithSource a -> ModuleSource getSource (WithSource s _) = s type ModuleWithSource = WithSource OpenModule instance ModSubst a => ModSubst (WithSource a) where modSubst subst (WithSource s m) = WithSource s (modSubst subst m)