Portability | GHC only |
---|---|

Stability | experimental |

Maintainer | ekmett@gmail.com |

Safe Haskell | None |

Root finding using Halley's rational method (the second in the class of Householder methods). Assumes the function is three times continuously differentiable and converges cubically when progress can be made.

- findZero :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> [a]
- inverse :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> a -> [a]
- fixedPoint :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> [a]
- extremum :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> [a]

# Halley's Method (Tower AD)

findZero :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> [a]Source

The `findZero`

function finds a zero of a scalar function using
Halley's method; its output is a stream of increasingly accurate
results. (Modulo the usual caveats.)

Examples:

`>>>`

[1.0,1.8571428571428572,1.9997967892704736,1.9999999999994755,2.0]`take 10 $ findZero (\x->x^2-4) 1`

`>>>`

`import Data.Complex`

`>>>`

0.0 :+ 1.0`last $ take 10 $ findZero ((+1).(^2)) (1 :+ 1)`

inverse :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> a -> [a]Source

The `inverse`

function inverts a scalar function using
Halley's method; its output is a stream of increasingly accurate
results. (Modulo the usual caveats.)

Note: the `take 10 $ inverse sqrt 1 (sqrt 10)`

example that works for Newton's method
fails with Halley's method because the preconditions do not hold!

fixedPoint :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> [a]Source

The `fixedPoint`

function find a fixedpoint of a scalar
function using Halley's method; its output is a stream of
increasingly accurate results. (Modulo the usual caveats.)

`>>>`

0.7390851332151607`last $ take 10 $ fixedPoint cos 1`

extremum :: (Fractional a, Eq a) => (forall s. Mode s => AD s a -> AD s a) -> a -> [a]Source

The `extremum`

function finds an extremum of a scalar
function using Halley's method; produces a stream of increasingly
accurate results. (Modulo the usual caveats.)

`>>>`

[1.0,0.29616942658570555,4.59979519460002e-3,1.6220740159042513e-8,0.0]`take 10 $ extremum cos 1`