-- | Burrito is a Haskell library for parsing and rendering URI templates. -- -- According to [RFC 6570](https://tools.ietf.org/html/rfc6570): "A URI -- Template is a compact sequence of characters for describing a range of -- Uniform Resource Identifiers through variable expansion." Burrito implements -- URI templates according to the specification in that RFC. -- -- The term "uniform resource identifiers" (URI) is often used interchangeably -- with other related terms like "internationalized resource identifier" (IRI), -- "uniform resource locator" (URL), and "uniform resource name" (URN). Burrito -- can be used for all of these. If you want to get technical, its input must -- be a valid IRI and its output will be a valid URI or URN. -- -- Although Burrito is primarily intended to be used with HTTP and HTTPS URIs, -- it should work with other schemes as well. -- -- If you're not already familiar with URI templates, I recommend reading the -- overview of the RFC. It's short, to the point, and easy to understand. -- -- Assuming you're familiar with URI templates, here's a simple example to show -- you how Burrito works: -- -- >>> import Burrito -- >>> let Just template = parse "http://example/search{?query}" -- >>> expand [("query", stringValue "chorizo")] template -- "http://example.com/search?query=chorizo" -- -- In short, use @parse@ to parse templates and @expand@ to render them. module Burrito ( Parse.parse , Render.render , Expand.expand , TH.uriTemplate , Template.Template , Value.Value , stringValue , listValue , dictionaryValue ) where import qualified Burrito.Expand as Expand import qualified Burrito.Parse as Parse import qualified Burrito.Render as Render import qualified Burrito.TH as TH import qualified Burrito.Type.Template as Template import qualified Burrito.Type.Value as Value -- | Constructs a string value. stringValue :: String -> Value.Value stringValue = Value.String -- | Constructs a list value. listValue :: [String] -> Value.Value listValue = Value.List -- | Constructs a dictionary value. dictionaryValue :: [(String, String)] -> Value.Value dictionaryValue = Value.Dictionary