Portability | non-portable (class-associated types) |
---|---|

Stability | experimental |

Maintainer | Edward Kmett <ekmett@gmail.com> |

Generalized functor composition. Since we have many reasons for which you might want to compose a functor, and many expected results. i.e. monads via adjunctions, monads via composition with a pointed endofunctor, etc. we have to make multiple composition operators.

- newtype CompF f g a = CompF {
- runCompF :: f (g a)

- class Composition o where
- associateComposition :: (Functor f, Composition c) => c (c f g) h a -> c f (c g h) a
- coassociateComposition :: (Functor f, Composition c) => c f (c g h) a -> c (c f g) h a
- type :.: = CompF
- data Comp p f g a b
- type :++: = Comp Either
- type :**: = Comp (,)
- liftComp :: Bifunctor p r s Hask => r (f a b) (f c d) -> s (g a b) (g c d) -> Comp p f g a b -> Comp p f g c d

# Documentation

Basic functor composition

Composition CompF | |

Functor f => HFunctor (CompF f) | |

(Functor f, Functor g) => Functor (CompF f g) | |

(Full f, Full g) => Full (CompF f g) | |

(ExpFunctor f, ExpFunctor g) => ExpFunctor (CompF f g) | |

(Adjunction f1 g1, Adjunction f2 g2) => Adjunction (CompF f2 f1) (CompF g1 g2) |

class Composition o whereSource

associateComposition :: (Functor f, Composition c) => c (c f g) h a -> c f (c g h) aSource

The only reason the compositions are all the same is for type inference. This can be liberalized.

coassociateComposition :: (Functor f, Composition c) => c f (c g h) a -> c (c f g) h aSource

Bifunctor composition

(Bifunctor p Hask Hask Hask, Symmetric Hask f, Symmetric Hask g) => Symmetric Hask (Comp p f g) | |

(Bifunctor p Hask Hask Hask, Braided Hask f, Braided Hask g) => Braided Hask (Comp p f g) | |

(Bifunctor p c d Hask, QFunctor f b c, QFunctor g b d) => QFunctor (Comp p f g) b Hask | |

(Bifunctor p c d Hask, PFunctor f a c, PFunctor g a d) => PFunctor (Comp p f g) a Hask | |

(Bifunctor p c d Hask, Bifunctor f a b c, Bifunctor g a b d) => Bifunctor (Comp p f g) a b Hask | |

(Bifunctor p Hask Hask Hask, Bifunctor f Hask Hask Hask, Bifunctor g Hask Hask Hask) => Functor (Comp p f g a) |