f1 = foo do bar

f2 = foo do
  bar

f3 = foo case True of
  True -> bar
  False -> baz

f4 = foo let a = 3 in b

f5 = foo let a = 3
             b = a
          in b

f6 = foo if bar
         then baz
         else not baz

f7 = foo \x -> y

f8 = foo \x ->
  y

f9 = foo do { bar } baz

f10 = foo
  do { a }
  do { b }
  do c

f11 = do a do b do c do d