{-# LANGUAGE MultiParamTypeClasses #-} {-# LANGUAGE FunctionalDependencies #-} {-# LANGUAGE FlexibleInstances #-} {-# LANGUAGE UndecidableInstances #-} ----------------------------------------------------------------------------- -- | -- Module : Control.Monad.Free.Class -- Copyright : (C) 2008-2011 Edward Kmett -- License : BSD-style (see the file LICENSE) -- -- Maintainer : Edward Kmett -- Stability : experimental -- Portability : non-portable (fundeps, MPTCs) -- -- Monads for free. ---------------------------------------------------------------------------- module Control.Monad.Free.Class ( MonadFree(..) ) where import Control.Applicative import Control.Monad.Trans.Reader import qualified Control.Monad.Trans.State.Strict as Strict import qualified Control.Monad.Trans.State.Lazy as Lazy import qualified Control.Monad.Trans.Writer.Strict as Strict import qualified Control.Monad.Trans.Writer.Lazy as Lazy import qualified Control.Monad.Trans.RWS.Strict as Strict import qualified Control.Monad.Trans.RWS.Lazy as Lazy import Control.Monad.Trans.Maybe import Control.Monad.Trans.List import Control.Monad.Trans.Error import Control.Monad.Trans.Identity import Data.Monoid -- | -- Monads provide substitution ('fmap') and renormalization ('Control.Monad.join'): -- -- @m '>>=' f = 'Control.Monad.join' . 'fmap' f m@ -- -- A free 'Monad' is one that does no work during the normalization step beyond simply grafting the two monadic values together. -- -- @[]@ is not a free 'Monad' (in this sense) because @'Control.Monad.join' [[a]]@ smashes the lists flat. -- -- On the other hand, consider: -- -- @ -- data Tree a = Bin (Tree a) (Tree a) | Tip a -- @ -- -- @ -- instance 'Monad' Tree where -- 'return' = Tip -- Tip a '>>=' f = f a -- Bin l r '>>=' f = Bin (l '>>=' f) (r '>>=' f) -- @ -- -- This 'Monad' is the free 'Monad' of Pair: -- -- @ -- data Pair a = Pair a a -- @ -- -- And we could make an instance of 'MonadFree' for it directly: -- -- @ -- instance 'MonadFree' Pair Tree where -- 'wrap' (Pair l r) = Bin l r -- @ -- -- Or we could choose to program with @'Control.Monad.Free.Free' Pair@ instead of 'Tree' -- and thereby avoid having to define our own 'Monad' instance. -- -- Moreover, the @kan-extensions@ package provides 'MonadFree' instances that can -- improve the /asymptotic/ complexity of code that constructors free monads by -- effectively reassociating the use of ('>>='). -- -- See 'Control.Monad.Free.Free' for a more formal definition of the free 'Monad' -- for a 'Functor'. class Monad m => MonadFree f m | m -> f where -- | Add a layer. wrap :: f (m a) -> m a instance (Functor f, MonadFree f m) => MonadFree f (ReaderT e m) where wrap fm = ReaderT $ \e -> wrap $ flip runReaderT e <$> fm instance (Functor f, MonadFree f m) => MonadFree f (Lazy.StateT s m) where wrap fm = Lazy.StateT $ \s -> wrap $ flip Lazy.runStateT s <$> fm instance (Functor f, MonadFree f m) => MonadFree f (Strict.StateT s m) where wrap fm = Strict.StateT $ \s -> wrap $ flip Strict.runStateT s <$> fm instance (Functor f, MonadFree f m, Monoid w) => MonadFree f (Lazy.WriterT w m) where wrap = Lazy.WriterT . wrap . fmap Lazy.runWriterT instance (Functor f, MonadFree f m, Monoid w) => MonadFree f (Strict.WriterT w m) where wrap = Strict.WriterT . wrap . fmap Strict.runWriterT instance (Functor f, MonadFree f m, Monoid w) => MonadFree f (Strict.RWST r w s m) where wrap fm = Strict.RWST $ \r s -> wrap $ fmap (\m -> Strict.runRWST m r s) fm instance (Functor f, MonadFree f m, Monoid w) => MonadFree f (Lazy.RWST r w s m) where wrap fm = Lazy.RWST $ \r s -> wrap $ fmap (\m -> Lazy.runRWST m r s) fm instance (Functor f, MonadFree f m) => MonadFree f (MaybeT m) where wrap = MaybeT . wrap . fmap runMaybeT instance (Functor f, MonadFree f m) => MonadFree f (IdentityT m) where wrap = IdentityT . wrap . fmap runIdentityT instance (Functor f, MonadFree f m) => MonadFree f (ListT m) where wrap = ListT . wrap . fmap runListT instance (Functor f, MonadFree f m, Error e) => MonadFree f (ErrorT e m) where wrap = ErrorT . wrap . fmap runErrorT