-- Hurkens' Paradox, a simplification of Girard's Paradox

-- (translated from Agda examples)

⊥ : Type;
⊥ = (α : Type) → α;

¬ : Type → Type;
¬ = λ α → α → ⊥;

P : Type → Type;
P = λ α → α → Type;

U : Type;
U = (χ : Type) → (P (P χ) → χ) → P (P χ);

τ : P (P U) → U;
τ = λ t χ f p → t (λ x → p (f (x χ f)));

σ : U → P (P U);
σ = λ s → s U (λ t → τ t);

Δ : P U;
Δ = λ y → ¬ ((p : P U) → σ y p → p (τ (σ y)));

Ω : U;
Ω = τ (λ p → (x : U) → σ x p → p x);

D : Type;
D = (p : P U) → σ Ω p → p (τ (σ Ω));

lem1 : (p : P U) → ((x : U) → σ x p → p x) → p Ω;
lem1 = λ p H1 → H1 Ω (λ x → H1 (τ (σ x)));

lem2 : ¬ D;
lem2 = lem1 Δ (λ x H2 H3 → H3 Δ H2 (λ p → H3 (λ y → p (τ (σ y)))));

lem3 : D;
lem3 = λ p → lem1 (λ y → p (τ (σ y)));

loop : ⊥;
loop = lem2 lem3;