----------------------------------------------------------------------------- -- | -- Module : Data.Functor.Extend -- Copyright : (C) 2011 Edward Kmett -- License : BSD-style (see the file LICENSE) -- -- Maintainer : Edward Kmett -- Stability : provisional -- Portability : portable -- ---------------------------------------------------------------------------- module Data.Functor.Extend ( -- * Extendable Functors -- $definition Extend(..) ) where import Prelude hiding (id, (.)) import Control.Category import Control.Monad.Trans.Identity import Data.Functor.Identity import Data.Semigroup import Data.List (tails) import Data.List.NonEmpty (NonEmpty(..), toList) import Data.Sequence (Seq) import qualified Data.Sequence as Seq import Data.Tree class Functor w => Extend w where -- | -- > duplicated = extended id -- > fmap (fmap f) . duplicated = duplicated . fmap f duplicated :: w a -> w (w a) -- | -- > extended f = fmap f . duplicated extended :: (w a -> b) -> w a -> w b extended f = fmap f . duplicated duplicated = extended id -- * Extends for Prelude types: -- -- Instances: While Data.Functor.Extend.Instances would be symmetric -- to the definition of Control.Monad.Instances in base, the reason -- the latter exists is because of Haskell 98 specifying the types -- @'Either' a@, @((,)m)@ and @((->)e)@ and the class Monad without -- having the foresight to require or allow instances between them. -- -- Here Haskell 98 says nothing about Extend, so we can include the -- instances directly avoiding the wart of orphan instances. instance Extend [] where duplicated = init . tails instance Extend Maybe where duplicated Nothing = Nothing duplicated j = Just j instance Extend (Either a) where duplicated (Left a) = Left a duplicated r = Right r instance Extend ((,)e) where duplicated p = (fst p, p) instance Semigroup m => Extend ((->)m) where duplicated f m = f . (<>) m instance Extend Seq where duplicated = Seq.tails instance Extend Tree where duplicated w@(Node _ as) = Node w (map duplicated as) -- I can't fix the world -- instance (Monoid m, Extend n) => Extend (ReaderT m n) -- duplicate f m = f . mappend m -- * Extends for types from 'transformers'. -- -- This isn't really a transformer, so i have no compunction about including the instance here. -- -- TODO: Petition to move Data.Functor.Identity into base instance Extend Identity where duplicated = Identity -- Provided to avoid an orphan instance. Not proposed to standardize. -- If Extend moved to base, consider moving instance into transformers? instance Extend w => Extend (IdentityT w) where extended f (IdentityT m) = IdentityT (extended (f . IdentityT) m) instance Extend NonEmpty where extended f w@ ~(_ :| aas) = f w :| case aas of [] -> [] (a:as) -> toList (extended f (a :| as)) -- $definition -- There are two ways to define an 'Extend' instance: -- -- I. Provide definitions for 'extend' -- satisfying this law: -- -- > extended f . extended g = extended (f . extended g) -- -- II. Alternately, you may choose to provide definitions for 'duplicate' -- satisfying this law: -- -- > duplicated . duplicated = fmap duplicated . duplicated -- -- These are both equivalent to the statement that (->-) is associative -- -- > (f ->- g) ->- h = f ->- (g ->- h) -- -- You may of course, choose to define both 'duplicate' /and/ 'extend'. -- In that case you must also satisfy these laws: -- -- > extended f = fmap f . duplicated -- > duplicated = extended id -- -- These are the default definitions of 'extended' and 'duplicated'.