-- | -- Copyright : (c) 2010,2012 Simon Meier -- License : GPL v3 (see LICENSE) -- -- Maintainer : Simon Meier -- -- Simple vertice list based representation of DAGs and some common operations on it. module Data.DAG.Simple ( -- * Computing with binary relations Relation , inverse , image , reachableSet , restrict -- ** Cycles , dfsLoopBreakers , cyclic , toposort ) where import Control.Basics import Control.Monad.Writer import Control.Monad.RWS import Data.List import qualified Data.DList as D import qualified Data.Set as S -- import Test.QuickCheck.Property (label) -- import Test.QuickCheck (quickCheck) -- | Produce a topological sorting of the given relation. If the relation is -- cyclic, then the result is at least some permutation of all elements of -- the given relation. toposort :: Ord a => [(a, a)] -> [a] toposort dag = execWriter . foldM visit S.empty $ map fst dag ++ map snd dag where visit visited x | x `S.member` visited = return visited | otherwise = foldM visit (S.insert x visited) preds <* tell (pure x) where preds = x `image` inverse dag -- | Compute the set of nodes reachable from the given set of nodes. reachableSet :: Ord a => [a] -> [(a,a)] -> S.Set a reachableSet start dag = foldl' visit S.empty start where visit visited x | x `S.member` visited = visited | otherwise = foldl' visit (S.insert x visited) (x `image` dag) -- | Is the relation cyclic. cyclic :: Ord a => [(a,a)] -> Bool cyclic rel = maybe True (const False) $ foldM visitForest S.empty $ map fst rel where visitForest visited x | x `S.member` visited = return visited | otherwise = findLoop S.empty visited x findLoop parents visited x | x `S.member` parents = mzero | x `S.member` visited = return visited | otherwise = S.insert x <$> foldM (findLoop parents') visited next where next = [ e' | (e,e') <- rel, e == x ] parents' = S.insert x parents -- TODO: Consider implementing something along the lines of Ann Becker, Dan -- Geiger, Optimization of Pearl's method of conditioning and greedy-like -- approximation algorithms for the vertex feedback set problem, Artificial -- Intelligence, Volume 83, Issue 1, May 1996, Pages 167-188, ISSN 0004-3702, -- 10.1016/0004-3702(95)00004-6. -- . -- | Compute a minimal set of loop-breakers using a greedy DFS strategy. A set -- of loop-breakers is a set of nodes such that removing them ensures the -- acyclicity of the relation. It is minimal, if no node can be removed from -- the set. dfsLoopBreakers :: Ord a => [(a,a)] -> [a] dfsLoopBreakers rel = D.toList $ snd $ execRWS (mapM_ (visit . fst) rel) () S.empty where visit x = do visited <- gets (S.member x) unless visited $ findLoopBreakers S.empty x -- PRE: x0 is not yet visited findLoopBreakers parents0 x = do modify (S.insert x) let parents = S.insert x parents0 ys = x `image` rel if any (`S.member` parents) ys then tell (return x) else forM_ ys $ \y -> do visited <- gets (S.member y) unless visited $ findLoopBreakers parents y -- | A relation represented as a list of tuples. type Relation a = [(a,a)] -- | Restrict a relation to elements satisfying a predicate. restrict :: Eq a => (a -> Bool) -> Relation a -> Relation a restrict p = filter (\(x,y) -> p x && p y) -- | The image of an element under a 'Relation'. image :: Eq a => a -> Relation a -> [a] image x rel = [ y' | (x', y') <- rel, x == x' ] -- | The inverse of a 'Relation'. inverse :: Relation a -> Relation a inverse rel = [ (y,x) | (x, y) <- rel ] {- prop_dfsLoopBreakers noSelfLoops rel0 | cyclic rel = label cycleLabel (minimal && not (cyclic (rel' breakers))) | otherwise = label "acyclic" (null breakers) where -- remove (x,x) entries in half of the cases removeSelfLoops | noSelfLoops = filter (not . (uncurry (==))) | otherwise = id -- restrict the relation to get more cyclic cases rel = removeSelfLoops $ map ((`mod` (20 :: Int)) *** (`mod` 20)) rel0 rel' bs = restrict (not . (`elem` bs)) rel breakers = dfsLoopBreakers rel cycleLabel | any (uncurry (==)) rel = "cyclic (with self-loop)" | otherwise = "cyclic (no self-loop)" -- true if loop breakers are minimal minimal = all (\b -> cyclic (rel' (filter (/= b) breakers))) breakers -}