triangulation-0.2: triangulation of polygons

Graphics.Triangulation.Triangulation

Synopsis

Documentation

data Tree Source

Constructors

Node Int Int [Tree] 

Instances

type F2 = (Float, Float)Source

triangulate :: TriangulationFunction -> Geometry -> GeometrySource

since there are a lot of triangulation algorithms a triangulation function can be passed

deleteHoles :: Geometry -> GeometrySource

some triangulation algorithms on't support polygons with holes These polygons with (nested) holes have to be cut so that they consist of only one outline I.e. the chars a,b,d,e,g,o,p,q contain holes tat have to be deleted.

embed :: Points -> [[Int]] -> [Int] -> [Int]Source

cut a polygon at a good position and insert the contained hole-polygon with opposite direction

alternate :: Int -> Bool -> [Int] -> [Int]Source

make sure that direction (clockwise or ccw) of polygons alternates depending on the nesting number c of poly

generateTrees :: Points -> (Points -> [Int] -> [Int] -> Bool) -> [[Int]] -> [Tree]Source

f should be the funtion to test contains the trees then are the hierarchy of containedness of outlines

treesList :: Points -> [[Int]] -> [Tree] -> [Tree]Source

rotatePoly :: Int -> Points -> [Int] -> (Int, Float)Source

how many positions to rotate a polygon until the start point is nearest to some other point call i.e. with nearest (3,4) [(0,0),(1,2), ... ] 0 0

nearest :: F2 -> [F2] -> Float -> Int -> Int -> (Int, Float)Source

insidePoly :: Points -> [Int] -> [Int] -> BoolSource

returns True iff the first point of the first polygon is inside the second poylgon

pointInside :: F2 -> [F2] -> BoolSource

A point is inside a polygon if it has an odd number of intersections with the boundary (Jordan Curve theorem)

polygonDirection :: [F2] -> BoolSource

the direction of a polygon can be obtained by looking at a maximal point returns True if counterclockwise False if clockwise