úΆdGFind sequences within a list and return them as new list of sequences. L The first argument is a function that takes two subsequent elements of the E given list (second argument) and returns whether the second element & follows the first one in a sequence. & splitSeq ((==) . succ) [1,2,3,5,6,7]  [[1,2,3],[5,6,7]] Works pretty much like $, except that a tuple with only the D sequence starting at the first element and the rest of the list is  returned. # spanSeq ((==) . succ) "abcxyz123"  ("abc","xyz123") data-list-sequences-0.1Data.List.SequencessplitSeqspanSeq