numeric-prelude-0.2: An experimental alternative hierarchy of numeric type classes

MathObj.PowerSeries.Core

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Synopsis

Documentation

evaluate :: C a => [a] -> a -> aSource

evaluateCoeffVector :: C a v => [v] -> a -> vSource

evaluateArgVector :: (C a v, C v) => [a] -> v -> vSource

approximate :: C a => [a] -> a -> [a]Source

approximateCoeffVector :: C a v => [v] -> a -> [v]Source

approximateArgVector :: (C a v, C v) => [a] -> v -> [v]Source

Simple series manipulation

alternate :: C a => [a] -> [a]Source

For the series of a real function f compute the series for x -> f (-x)

holes2 :: C a => [a] -> [a]Source

For the series of a real function f compute the series for x -> (f x + f (-x)) / 2

holes2alternate :: C a => [a] -> [a]Source

For the series of a real function f compute the real series for x -> (f (i*x) + f (-i*x)) / 2

Series arithmetic

sub :: C a => [a] -> [a] -> [a]Source

add :: C a => [a] -> [a] -> [a]Source

negate :: C a => [a] -> [a]Source

scale :: C a => a -> [a] -> [a]Source

mul :: C a => [a] -> [a] -> [a]Source

stripLeadZero :: C a => [a] -> [a] -> ([a], [a])Source

divMod :: (C a, C a) => [a] -> [a] -> ([a], [a])Source

divide :: C a => [a] -> [a] -> [a]Source

Divide two series where the absolute term of the divisor is non-zero. That is, power series with leading non-zero terms are the units in the ring of power series.

Knuth: Seminumerical algorithms

divideStripZero :: (C a, C a) => [a] -> [a] -> [a]Source

Divide two series also if the divisor has leading zeros.

progression :: C a => [a]Source

differentiate :: C a => [a] -> [a]Source

integrate :: C a => a -> [a] -> [a]Source

sqrt :: C a => (a -> a) -> [a] -> [a]Source

We need to compute the square root only of the first term. That is, if the first term is rational, then all terms of the series are rational.

pow :: C a => (a -> a) -> a -> [a] -> [a]Source

Input series must start with non-zero term.

exp :: C a => (a -> a) -> [a] -> [a]Source

The first term needs a transcendent computation but the others do not. That's why we accept a function which computes the first term.

 (exp . x)' =   (exp . x) * x'
 (sin . x)' =   (cos . x) * x'
 (cos . x)' = - (sin . x) * x'

sinCos :: C a => (a -> (a, a)) -> [a] -> ([a], [a])Source

sinCosScalar :: C a => a -> (a, a)Source

cos :: C a => (a -> (a, a)) -> [a] -> [a]Source

sin :: C a => (a -> (a, a)) -> [a] -> [a]Source

tan :: C a => (a -> (a, a)) -> [a] -> [a]Source

log :: C a => (a -> a) -> [a] -> [a]Source

Input series must start with non-zero term.

derivedLog :: C a => [a] -> [a]Source

Computes (log x)', that is x'/x

atan :: C a => (a -> a) -> [a] -> [a]Source

acos :: C a => (a -> a) -> (a -> a) -> [a] -> [a]Source

asin :: C a => (a -> a) -> (a -> a) -> [a] -> [a]Source

compose :: C a => [a] -> [a] -> [a]Source

Since the inner series must start with a zero, the first term is omitted in y.

composeTaylor :: C a => (a -> [a]) -> [a] -> [a]Source

Compose two power series where the outer series can be developed for any expansion point. To be more precise: The outer series must be expanded with respect to the leading term of the inner series.

inv :: C a => [a] -> (a, [a])Source

This function returns the series of the function in the form: (point of the expansion, power series)

This is exceptionally slow and needs cubic run-time.