----------------------------------------------------------------------------- -- | -- Module : Documentation.SBV.Examples.Uninterpreted.UISortAllSat -- Author : Levent Erkok -- License : BSD3 -- Maintainer: erkokl@gmail.com -- Stability : experimental -- -- Demonstrates uninterpreted sorts and how all-sat behaves for them. -- Thanks to Eric Seidel for the idea. ----------------------------------------------------------------------------- {-# LANGUAGE DeriveDataTypeable #-} module Documentation.SBV.Examples.Uninterpreted.UISortAllSat where import Data.Generics import Data.SBV -- | A "list-like" data type, but one we plan to uninterpret at the SMT level. -- The actual shape is really immaterial for us, but could be used as a proxy -- to generate test cases or explore data-space in some other part of a program. -- Note that we neither rely on the shape of this data, nor need the actual -- constructors. data L = Nil | Cons Int L deriving (Eq, Ord, Show, Read, Data) -- | Declare instances to make 'L' a usable uninterpreted sort. First we need the -- 'SymVal' instance, with the default definition sufficing. instance SymVal L -- | Similarly, 'HasKind's default implementation is sufficient. instance HasKind L -- | An uninterpreted "classify" function. Really, we only care about -- the fact that such a function exists, not what it does. classify :: SBV L -> SInteger classify = uninterpret "classify" -- | Formulate a query that essentially asserts a cardinality constraint on -- the uninterpreted sort 'L'. The goal is to say there are precisely 3 -- such things, as it might be the case. We manage this by declaring four -- elements, and asserting that for a free variable of this sort, the -- shape of the data matches one of these three instances. That is, we -- assert that all the instances of the data 'L' can be classified into -- 3 equivalence classes. Then, allSat returns all the possible instances, -- which of course are all uninterpreted. -- -- As expected, we have: -- -- >>> genLs -- Solution #1: -- l = L!val!0 :: L -- l0 = L!val!0 :: L -- l1 = L!val!1 :: L -- l2 = L!val!2 :: L -- Solution #2: -- l = L!val!1 :: L -- l0 = L!val!0 :: L -- l1 = L!val!1 :: L -- l2 = L!val!2 :: L -- Solution #3: -- l = L!val!2 :: L -- l0 = L!val!0 :: L -- l1 = L!val!1 :: L -- l2 = L!val!2 :: L -- Found 3 different solutions. genLs :: IO AllSatResult genLs = allSatWith z3 $ do [l, l0, l1, l2] <- symbolics ["l", "l0", "l1", "l2"] constrain $ classify l0 .== 0 constrain $ classify l1 .== 1 constrain $ classify l2 .== 2 return $ l .== l0 .|| l .== l1 .|| l .== l2