----------------------------------------------------------------------------- -- | -- Module : Documentation.SBV.Examples.Puzzles.HexPuzzle -- Copyright : (c) Levent Erkok -- License : BSD3 -- Maintainer: erkokl@gmail.com -- Stability : experimental -- -- A solution to the hexagon solver puzzle: -- In case the above URL goes dead, here's an ASCII rendering of the problem. -- -- We're given a board, with 19 hexagon cells. The cells are arranged as follows: -- -- @ -- 01 02 03 -- 04 05 06 07 -- 08 09 10 11 12 -- 13 14 15 16 -- 17 18 19 -- @ -- -- - Each cell has a color, one of @BLACK@, @BLUE@, @GREEN@, or @RED@. -- -- - At each step, you get to press one of the center buttons. That is, -- one of 5, 6, 9, 10, 11, 14, or 15. -- -- - Pressing a button that is currently colored @BLACK@ has no effect. -- -- - Otherwise (i.e., if the pressed button is not @BLACK@), then colors -- rotate clockwise around that button. For instance if you press 15 -- when it is not colored @BLACK@, then 11 moves to 16, 16 moves to 19, -- 19 moves to 18, 18 moves to 14, 14 moves to 10, and 10 moves to 11. -- -- - Note that by "move," we mean the colors move: We still refer to the buttons -- with the same number after a move. -- -- You are given an initial board coloring, and a final one. Your goal is -- to find a minimal sequence of button presses that will turn the original board -- to the final one. ----------------------------------------------------------------------------- {-# LANGUAGE DeriveAnyClass #-} {-# LANGUAGE DeriveDataTypeable #-} {-# LANGUAGE ScopedTypeVariables #-} {-# LANGUAGE StandaloneDeriving #-} {-# LANGUAGE TemplateHaskell #-} module Documentation.SBV.Examples.Puzzles.HexPuzzle where import Data.SBV import Data.SBV.Control -- | Colors we're allowed data Color = Black | Blue | Green | Red -- | Make 'Color' a symbolic value. mkSymbolicEnumeration ''Color -- | Give symbolic colors a name for convenience. type SColor = SBV Color -- | Use 8-bit words for button numbers, even though we only have 1 to 19. type Button = Word8 -- | Symbolic version of button. type SButton = SBV Button -- | The grid is an array mapping each button to its color. type Grid = SFunArray Button Color -- | Given a button press, and the current grid, compute the next grid. -- If the button is "unpressable", i.e., if it is not one of the center -- buttons or it is currently colored black, we return the grid unchanged. next :: SButton -> Grid -> Grid next b g = ite (readArray g b .== literal Black) g $ ite (b .== 5) (rot [ 1, 2, 6, 10, 9, 4]) $ ite (b .== 6) (rot [ 2, 3, 7, 11, 10, 5]) $ ite (b .== 9) (rot [ 4, 5, 10, 14, 13, 8]) $ ite (b .== 10) (rot [ 5, 6, 11, 15, 14, 9]) $ ite (b .== 11) (rot [ 6, 7, 12, 16, 15, 10]) $ ite (b .== 14) (rot [ 9, 10, 15, 18, 17, 13]) $ ite (b .== 15) (rot [10, 11, 16, 19, 18, 14]) g where rot xs = foldr (\(i, c) a -> writeArray a (literal i) c) g (zip new cur) where cur = map (readArray g . literal) xs new = tail xs ++ [head xs] -- | Iteratively search at increasing depths of button-presses to see if we can -- transform from the initial board position to a final board position. search :: [Color] -> [Color] -> IO () search initial final = runSMT $ do emptyGrid :: Grid <- newArray "emptyGrid" (Just (literal Black)) let initGrid = foldr (\(i, c) a -> writeArray a (literal i) (literal c)) emptyGrid (zip [1..] initial) query $ loop (0 :: Int) initGrid [] where loop i g sofar = do io $ putStrLn $ "Searching at depth: " ++ show i -- Go into a new context, and see if we've reached a solution: push 1 constrain $ map (readArray g . literal) [1..19] .== map literal final cs <- checkSat case cs of Unk -> error $ "Solver said Unknown, depth: " ++ show i Unsat -> do -- It didn't work out. Pop and try again with one more move: pop 1 b <- freshVar ("press_" ++ show i) constrain $ b `sElem` map literal [5, 6, 9, 10, 11, 14, 15] loop (i+1) (next b g) (sofar ++ [b]) Sat -> do vs <- mapM getValue sofar io $ putStrLn $ "Found: " ++ show vs findOthers sofar vs findOthers vs = go where go curVals = do constrain $ sOr $ zipWith (\v c -> v ./= literal c) vs curVals cs <- checkSat case cs of Unk -> error "Unknown!" Unsat -> io $ putStrLn "There are no more solutions." Sat -> do newVals <- mapM getValue vs io $ putStrLn $ "Found: " ++ show newVals go newVals -- | A particular example run. We have: -- -- >>> example -- Searching at depth: 0 -- Searching at depth: 1 -- Searching at depth: 2 -- Searching at depth: 3 -- Searching at depth: 4 -- Searching at depth: 5 -- Searching at depth: 6 -- Found: [10,10,11,9,14,6] -- Found: [10,10,9,11,14,6] -- There are no more solutions. example :: IO () example = search initBoard finalBoard where initBoard = [Black, Black, Black, Red, Blue, Green, Red, Black, Green, Green, Green, Black, Red, Green, Green, Red, Black, Black, Black] finalBoard = [Black, Red, Black, Black, Green, Green, Black, Red, Green, Blue, Green, Red, Black, Green, Green, Black, Black, Red, Black]