clash-prelude-0.10.3: CAES Language for Synchronous Hardware - Prelude library

Copyright(C) 2013-2015, University of Twente
LicenseBSD2 (see the file LICENSE)
MaintainerChristiaan Baaij <christiaan.baaij@gmail.com>
Safe HaskellTrustworthy
LanguageHaskell2010
Extensions
  • UndecidableInstances
  • MonoLocalBinds
  • TemplateHaskell
  • ScopedTypeVariables
  • BangPatterns
  • TypeFamilies
  • ViewPatterns
  • GADTs
  • GADTSyntax
  • DataKinds
  • FlexibleContexts
  • MagicHash
  • KindSignatures
  • TupleSections
  • RankNTypes
  • TypeOperators
  • ExplicitNamespaces
  • ExplicitForAll
  • PatternSynonyms

CLaSH.Sized.Vector

Contents

Description

 

Synopsis

Vector data type

data Vec :: Nat -> * -> * where Source

Fixed size vectors.

  • Lists with their length encoded in their type
  • Vector elements have an ASCENDING subscript starting from 0 and ending at maxIndex (== length - 1).

Constructors

Nil :: Vec 0 a 
Cons :: a -> Vec n a -> Vec (n + 1) a infixr 5

Warning: Use :> instead of Cons

Instances

Functor (Vec n) Source 
KnownNat n => Applicative (Vec n) Source 
(KnownNat m, (~) Nat m ((+) n 1)) => Foldable (Vec m) Source 
(KnownNat m, (~) Nat m ((+) n 1)) => Traversable (Vec m) Source 
Eq a => Eq (Vec n a) Source 
Ord a => Ord (Vec n a) Source 
Show a => Show (Vec n a) Source 
(KnownNat n, Arbitrary a) => Arbitrary (Vec n a) Source 
CoArbitrary a => CoArbitrary (Vec n a) Source 
(Default a, KnownNat n) => Default (Vec n a) Source 
KnownNat n => Ixed (Vec n a) Source 
Lift a => Lift (Vec n a) Source 
(KnownNat n, KnownNat (BitSize a), BitPack a) => BitPack (Vec n a) Source 
KnownNat n => Bundle (Vec n a) Source 
type Unbundled' t (Vec n a) = Vec n (Signal' t a) Source 
type Index (Vec n a) = Int Source 
type IxValue (Vec n a) = a Source 
type BitSize (Vec n a) = * n (BitSize a) Source 

Accessors

Length information

length :: KnownNat n => Vec n a -> Int Source

The length of a Vector as an Int value.

>>> length (6 :> 7 :> 8 :> Nil)
3

maxIndex :: KnownNat n => Vec n a -> Int Source

The index (subscript) of the last element in a Vector as an Int value.

>>> maxIndex (6 :> 7 :> 8 :> Nil)
2

lengthS :: KnownNat n => Vec n a -> SNat n Source

Length of a Vector as an SNat value

Indexing

(!!) :: (KnownNat n, Enum i) => Vec n a -> i -> a Source

"xs !! n" returns the n'th element of xs.

NB: vector elements have an ASCENDING subscript starting from 0 and ending at maxIndex.

>>> (1:>2:>3:>4:>5:>Nil) !! 4
5
>>> (1:>2:>3:>4:>5:>Nil) !! maxIndex (1:>2:>3:>4:>5:>Nil)
5
>>> (1:>2:>3:>4:>5:>Nil) !! 1
2
>>> (1:>2:>3:>4:>5:>Nil) !! 14
*** Exception: CLaSH.Sized.Vector.(!!): index 14 is larger than maximum index 4

head :: Vec (n + 1) a -> a Source

Extract the first element of a vector

>>> head (1:>2:>3:>Nil)
1
>>> head Nil

<interactive>:...
    Couldn't match type ‘...’ with ‘0’
    Expected type: Vec ... a
      Actual type: Vec 0 a
    In the first argument of ‘head’, namely ‘Nil’
    In the expression: head Nil

last :: Vec (n + 1) a -> a Source

Extract the last element of a vector

>>> last (1:>2:>3:>Nil)
3
>>> last Nil

<interactive>:...
    Couldn't match type ‘...’ with ‘0’
    Expected type: Vec ... a
      Actual type: Vec 0 a
    In the first argument of ‘last’, namely ‘Nil’
    In the expression: last Nil

at :: SNat m -> Vec (m + (n + 1)) a -> a Source

"at n xs" returns n'th element of xs

NB: vector elements have an ASCENDING subscript starting from 0 and ending at maxIndex.

>>> at (snat :: SNat 1) (1:>2:>3:>4:>5:>Nil)
2
>>> at d1               (1:>2:>3:>4:>5:>Nil)
2

indices :: KnownNat n => SNat n -> Vec n (Index n) Source

Generate a vector of indices.

>>> indices d4
<0,1,2,3>

indicesI :: KnownNat n => Vec n (Index n) Source

Generate a vector of indices, where the length of the vector is determined by the context.

>>> indicesI :: Vec 4 (Index 4)
<0,1,2,3>

findIndex :: KnownNat n => (a -> Bool) -> Vec n a -> Maybe (Index n) Source

"findIndex p xs" returns the index of the first element of xs satisfying the predicate p, or Nothing if there is no such element.

>>> findIndex (> 3) (1:>3:>2:>4:>3:>5:>6:>Nil)
Just 3
>>> findIndex (> 8) (1:>3:>2:>4:>3:>5:>6:>Nil)
Nothing

elemIndex :: (KnownNat n, Eq a) => a -> Vec n a -> Maybe (Index n) Source

"elemIndex a xs" returns the index of the first element which is equal (by ==) to the query element a, or Nothing if there is no such element.

>>> elemIndex 3 (1:>3:>2:>4:>3:>5:>6:>Nil)
Just 1
>>> elemIndex 8 (1:>3:>2:>4:>3:>5:>6:>Nil)
Nothing

Extracting sub-vectors (slicing)

tail :: Vec (n + 1) a -> Vec n a Source

Extract the elements after the head of a vector

>>> tail (1:>2:>3:>Nil)
<2,3>
>>> tail Nil

<interactive>:...
    Couldn't match type ‘...’ with ‘0’
    Expected type: Vec ... a
      Actual type: Vec 0 a
    In the first argument of ‘tail’, namely ‘Nil’
    In the expression: tail Nil

init :: Vec (n + 1) a -> Vec n a Source

Extract all the elements of a vector except the last element

>>> init (1:>2:>3:>Nil)
<1,2>
>>> init Nil

<interactive>:...
    Couldn't match type ‘...’ with ‘0’
    Expected type: Vec ... a
      Actual type: Vec 0 a
    In the first argument of ‘init’, namely ‘Nil’
    In the expression: init Nil

take :: SNat m -> Vec (m + n) a -> Vec m a Source

"take n xs" returns the n-length prefix of xs.

>>> take (snat :: SNat 3) (1:>2:>3:>4:>5:>Nil)
<1,2,3>
>>> take d3               (1:>2:>3:>4:>5:>Nil)
<1,2,3>
>>> take d0               (1:>2:>Nil)
<>
>>> take d4               (1:>2:>Nil)

<interactive>:...
    Couldn't match type ‘4 + n0’ with ‘2’
    The type variable ‘n0’ is ambiguous
    Expected type: Vec (4 + n0) a
      Actual type: Vec (1 + 1) a
    In the second argument of ‘take’, namely ‘(1 :> 2 :> Nil)’
    In the expression: take d4 (1 :> 2 :> Nil)
    In an equation for ‘it’: it = take d4 (1 :> 2 :> Nil)

takeI :: KnownNat m => Vec (m + n) a -> Vec m a Source

"takeI xs" returns the prefix of xs as demanded by the context.

>>> takeI (1:>2:>3:>4:>5:>Nil) :: Vec 2 Int
<1,2>

drop :: SNat m -> Vec (m + n) a -> Vec n a Source

"drop n xs" returns the suffix of xs after the first n elements.

>>> drop (snat :: SNat 3) (1:>2:>3:>4:>5:>Nil)
<4,5>
>>> drop d3               (1:>2:>3:>4:>5:>Nil)
<4,5>
>>> drop d0               (1:>2:>Nil)
<1,2>
>>> drop d4               (1:>2:>Nil)

<interactive>:...
    Couldn't match expected type ‘2’ with actual type ‘4 + n0’
    The type variable ‘n0’ is ambiguous
    In the first argument of ‘print’, namely ‘it’
    In a stmt of an interactive GHCi command: print it

dropI :: KnownNat m => Vec (m + n) a -> Vec n a Source

"dropI xs" returns the suffix of xs as demanded by the context.

>>> dropI (1:>2:>3:>4:>5:>Nil) :: Vec 2 Int
<4,5>

select :: (CmpNat (i + s) (s * n) ~ GT) => SNat f -> SNat s -> SNat n -> Vec (f + i) a -> Vec n a Source

"select f s n xs" selects n elements with step-size s and offset f from xs.

>>> select (snat :: SNat 1) (snat :: SNat 2) (snat :: SNat 3) (1:>2:>3:>4:>5:>6:>7:>8:>Nil)
<2,4,6>
>>> select d1 d2 d3 (1:>2:>3:>4:>5:>6:>7:>8:>Nil)
<2,4,6>

selectI :: (CmpNat (i + s) (s * n) ~ GT, KnownNat n) => SNat f -> SNat s -> Vec (f + i) a -> Vec n a Source

"selectI f s xs" selects as many elements as demanded by the context with step-size s and offset f from xs.

>>> selectI d1 d2 (1:>2:>3:>4:>5:>6:>7:>8:>Nil) :: Vec 2 Int
<2,4>

Splitting

splitAt :: SNat m -> Vec (m + n) a -> (Vec m a, Vec n a) Source

Split a vector into two vectors at the given point.

>>> splitAt (snat :: SNat 3) (1:>2:>3:>7:>8:>Nil)
(<1,2,3>,<7,8>)
>>> splitAt d3 (1:>2:>3:>7:>8:>Nil)
(<1,2,3>,<7,8>)

splitAtI :: KnownNat m => Vec (m + n) a -> (Vec m a, Vec n a) Source

Split a vector into two vectors where the length of the two is determined by the context.

>>> splitAtI (1:>2:>3:>7:>8:>Nil) :: (Vec 2 Int, Vec 3 Int)
(<1,2>,<3,7,8>)

unconcat :: KnownNat n => SNat m -> Vec (n * m) a -> Vec n (Vec m a) Source

Split a vector of (n * m) elements into a vector of "vectors of length m", where the length m is given.

>>> unconcat d4 (1:>2:>3:>4:>5:>6:>7:>8:>9:>10:>11:>12:>Nil)
<<1,2,3,4>,<5,6,7,8>,<9,10,11,12>>

unconcatI :: (KnownNat n, KnownNat m) => Vec (n * m) a -> Vec n (Vec m a) Source

Split a vector of (n * m) elements into a vector of "vectors of length m", where the length m is determined by the context.

>>> unconcatI (1:>2:>3:>4:>5:>6:>7:>8:>9:>10:>11:>12:>Nil) :: Vec 2 (Vec 6 Int)
<<1,2,3,4,5,6>,<7,8,9,10,11,12>>

Construction

Initialisation

singleton :: a -> Vec 1 a Source

Create a vector of one element

>>> singleton 5
<5>

replicate :: SNat n -> a -> Vec n a Source

"replicate n a" returns a vector that has n copies of a.

>>> replicate (snat :: SNat 3) 6
<6,6,6>
>>> replicate d3 6
<6,6,6>

replicateI :: KnownNat n => a -> Vec n a Source

Warning: Use repeat instead of replicateI

"replicateI a" creates a vector with as many copies of a as demanded by the context.

>>> replicateI 6 :: Vec 5 Int
<6,6,6,6,6>

repeat :: KnownNat n => a -> Vec n a Source

"repeat a" creates a vector with as many copies of a as demanded by the context.

>>> repeat 6 :: Vec 5 Int
<6,6,6,6,6>

iterate :: SNat n -> (a -> a) -> a -> Vec n a Source

"iterate n f x" returns a vector starting with x followed by n repeated applications of f to x.

iterate (snat :: SNat 4) f x == (x :> f x :> f (f x) :> f (f (f x)) :> Nil)
iterate d4 f x               == (x :> f x :> f (f x) :> f (f (f x)) :> Nil)
>>> iterate d4 (+1) 1
<1,2,3,4>

"interate n f z" corresponds to the following circuit layout:

iterateI :: KnownNat n => (a -> a) -> a -> Vec n a Source

"iterate f x" returns a vector starting with x followed by n repeated applications of f to x, where n is determined by the context.

iterateI f x :: Vec 3 a == (x :> f x :> f (f x) :> Nil)
>>> iterateI (+1) 1 :: Vec 3 Int
<1,2,3>

"interateI f z" corresponds to the following circuit layout:

generate :: SNat n -> (a -> a) -> a -> Vec n a Source

"generate n f x" returns a vector with n repeated applications of f to x.

generate (snat :: SNat 4) f x == (f x :> f (f x) :> f (f (f x)) :> f (f (f (f x))) :> Nil)
generate d4 f x               == (f x :> f (f x) :> f (f (f x)) :> f (f (f (f x))) :> Nil)
>>> generate d4 (+1) 1
<2,3,4,5>

"generate n f z" corresponds to the following circuit layout:

generateI :: KnownNat n => (a -> a) -> a -> Vec n a Source

"generateI f x" returns a vector with n repeated applications of f to x, where n is determined by the context.

generateI f x :: Vec 3 a == (f x :> f (f x) :> f (f (f x)) :> Nil)
>>> generateI (+1) 1 :: Vec 3 Int
<2,3,4>

"generateI f z" corresponds to the following circuit layout:

Initialisation from a list

v :: Lift a => [a] -> ExpQ Source

Create a vector literal from a list literal.

$(v [1::Signed 8,2,3,4,5]) == (8:>2:>3:>4:>5:>Nil) :: Vec 5 (Signed 8)
>>> [1 :: Signed 8,2,3,4,5]
[1,2,3,4,5]
>>> $(v [1::Signed 8,2,3,4,5])
<1,2,3,4,5>

Concatenation

pattern (:>) :: a -> Vec n a -> Vec ((+) n 1) a infixr 5 Source

Add an element to the head of a vector.

>>> 3:>4:>5:>Nil
<3,4,5>
>>> let x = 3:>4:>5:>Nil
>>> :t x
x :: Num a => Vec 3 a

Can be used as a pattern:

>>> let f (x :> y :> _) = x + y
>>> :t f
f :: Num a => Vec ((n + 1) + 1) a -> a
>>> f (3:>4:>5:>6:>7:>Nil)
7

Also in conjunctions with (:<):

>>> let g (a :> b :> (_ :< y :< x)) = a + b +  x + y
>>> :t g
g :: Num a => Vec ((((n + 1) + 1) + 1) + 1) a -> a
>>> g (1:>2:>3:>4:>5:>Nil)
12

pattern (:<) :: Vec n a -> a -> Vec ((+) n 1) a infixl 5 Source

Add an element to the tail of a vector.

>>> (3:>4:>5:>Nil) :< 1
<3,4,5,1>
>>> let x = (3:>4:>5:>Nil) :< 1
>>> :t x
x :: Num a => Vec 4 a

Can be used as a pattern:

>>> let f (_ :< y :< x) = y + x
>>> :t f
f :: Num a => Vec ((n + 1) + 1) a -> a
>>> f (3:>4:>5:>6:>7:>Nil)
13

Also in conjunctions with (:>):

>>> let g (a :> b :> (_ :< y :< x)) = a + b +  x + y
>>> :t g
g :: Num a => Vec ((((n + 1) + 1) + 1) + 1) a -> a
>>> g (1:>2:>3:>4:>5:>Nil)
12

(++) :: Vec n a -> Vec m a -> Vec (n + m) a infixr 5 Source

Append two vectors.

>>> (1:>2:>3:>Nil) ++ (7:>8:>Nil)
<1,2,3,7,8>

(+>>) :: KnownNat n => a -> Vec n a -> Vec n a infixr 4 Source

Add an element to the head of a vector, and extract all but the last element.

>>> 1 +>> (3:>4:>5:>Nil)
<1,3,4>
>>> 1 +>> Nil
<>

(<<+) :: Vec n a -> a -> Vec n a infixl 4 Source

Add an element to the tail of a vector, and extract all but the first element.

>>> (3:>4:>5:>Nil) <<+ 1
<4,5,1>
>>> Nil <<+ 1
<>

concat :: Vec n (Vec m a) -> Vec (n * m) a Source

Concatenate a vector of vectors.

>>> concat ((1:>2:>3:>Nil) :> (4:>5:>6:>Nil) :> (7:>8:>9:>Nil) :> (10:>11:>12:>Nil) :> Nil)
<1,2,3,4,5,6,7,8,9,10,11,12>

shiftInAt0 Source

Arguments

:: KnownNat n 
=> Vec n a

The old vector

-> Vec m a

The elements to shift in at the head

-> (Vec n a, Vec m a)

(The new vector, shifted out elements)

Shift in elements to the head of a vector, bumping out elements at the tail. The result is a tuple containing:

  • The new vector
  • The shifted out elements
>>> shiftInAt0 (1 :> 2 :> 3 :> 4 :> Nil) ((-1) :> 0 :> Nil)
(<-1,0,1,2>,<3,4>)
>>> shiftInAt0 (1 :> Nil) ((-1) :> 0 :> Nil)
(<-1>,<0,1>)

shiftInAtN Source

Arguments

:: KnownNat m 
=> Vec n a

The old vector

-> Vec m a

The elements to shift in at the tail

-> (Vec n a, Vec m a)

(The new vector, shifted out elements)

Shift in element to the tail of a vector, bumping out elements at the head. The result is a tuple containing:

  • The new vector
  • The shifted out elements
>>> shiftInAtN (1 :> 2 :> 3 :> 4 :> Nil) (5 :> 6 :> Nil)
(<3,4,5,6>,<1,2>)
>>> shiftInAtN (1 :> Nil) (2 :> 3 :> Nil)
(<3>,<1,2>)

shiftOutFrom0 Source

Arguments

:: (Default a, KnownNat m) 
=> SNat m

m, the number of elements to shift out

-> Vec (m + n) a

The old vector

-> (Vec (m + n) a, Vec m a)

(The new vector, shifted out elements)

Shift m elements out from the head of a vector, filling up the tail with Default values. The result is a tuple containing:

  • The new vector
  • The shifted out values
>>> shiftOutFrom0 d2 ((1 :> 2 :> 3 :> 4 :> 5 :> Nil) :: Vec 5 Integer)
(<3,4,5,0,0>,<1,2>)

shiftOutFromN Source

Arguments

:: (Default a, KnownNat (m + n)) 
=> SNat m

m, the number of elements to shift out

-> Vec (m + n) a

The old vector

-> (Vec (m + n) a, Vec m a)

(The new vector, shifted out elements)

Shift m elements out from the tail of a vector, filling up the head with Default values. The result is a tuple containing:

  • The new vector
  • The shifted out values
>>> shiftOutFromN d2 ((1 :> 2 :> 3 :> 4 :> 5 :> Nil) :: Vec 5 Integer)
(<0,0,1,2,3>,<4,5>)

merge :: KnownNat n => Vec n a -> Vec n a -> Vec (2 * n) a Source

Merge two vectors, alternating their elements, i.e.,

>>> merge (1 :> 2 :> 3 :> 4 :> Nil) (5 :> 6 :> 7 :> 8 :> Nil)
<1,5,2,6,3,7,4,8>

Modifying vectors

replace :: (KnownNat n, Enum i) => i -> a -> Vec n a -> Vec n a Source

"replace n a xs" returns the vector xs where the n'th element is replaced by a.

NB: vector elements have an ASCENDING subscript starting from 0 and ending at maxIndex.

>>> replace 3 7 (1:>2:>3:>4:>5:>Nil)
<1,2,3,7,5>
>>> replace 0 7 (1:>2:>3:>4:>5:>Nil)
<7,2,3,4,5>
>>> replace 9 7 (1:>2:>3:>4:>5:>Nil)
<1,2,3,4,*** Exception: CLaSH.Sized.Vector.replace: index 9 is larger than maximum index 4

Permutations

permute Source

Arguments

:: (Enum i, KnownNat n, KnownNat m) 
=> (a -> a -> a)

Combination function, f

-> Vec n a

Default values, def

-> Vec m i

Index mapping, is

-> Vec (m + k) a

Vector to be permuted, xs

-> Vec n a 

Forward permutation specified by an index mapping, ix. The result vector is initialised by the given defaults, def, and an further values that are permuted into the result are added to the current value using the given combination function, f.

The combination function must be associative and commutative.

backpermute Source

Arguments

:: (Enum i, KnownNat n) 
=> Vec n a

Source vector, xs

-> Vec m i

Index mapping, is

-> Vec m a 

Backwards permutation specified by an index mapping, is, from the destination vector specifying which element of the source vector xs to read.

"backpermute xs is" is equivalent to "map (xs !!) is".

For example:

>>> let input = 1:>9:>6:>4:>4:>2:>0:>1:>2:>Nil
>>> let from  = 1:>3:>7:>2:>5:>3:>Nil
>>> backpermute input from
<9,4,1,6,2,4>

scatter Source

Arguments

:: (Enum i, KnownNat n, KnownNat m) 
=> Vec n a

Default values, def

-> Vec m i

Index mapping, is

-> Vec (m + k) a

Vector to be scattered, xs

-> Vec n a 

Copy elements from the source vector, xs, to the destination vector according to an index mapping is. This is a forward permute operation where a to vector encodes an input to output index mapping. Output elements for indices that are not mapped assume the value in the default vector def.

For example:

>>> let defVec = 0:>0:>0:>0:>0:>0:>0:>0:>0:>Nil
>>> let to = 1:>3:>7:>2:>5:>8:>Nil
>>> let input = 1:>9:>6:>4:>4:>2:>5:>Nil
>>> scatter defVec to input
<0,1,4,9,0,4,0,6,2>

NB: If the same index appears in the index mapping more than once, the latest mapping is chosen.

gather Source

Arguments

:: (Enum i, KnownNat n) 
=> Vec n a

Source vector, xs

-> Vec m i

Index mapping, is

-> Vec m a 

Backwards permutation specified by an index mapping, is, from the destination vector specifying which element of the source vector xs to read.

"gather xs is" is equivalent to "map (xs !!) is".

For example:

>>> let input = 1:>9:>6:>4:>4:>2:>0:>1:>2:>Nil
>>> let from  = 1:>3:>7:>2:>5:>3:>Nil
>>> gather input from
<9,4,1,6,2,4>

Specialised permutations

reverse :: Vec n a -> Vec n a Source

The elements in a vector in reverse order.

>>> reverse (1:>2:>3:>4:>Nil)
<4,3,2,1>

transpose :: KnownNat n => Vec m (Vec n a) -> Vec n (Vec m a) Source

Transpose a matrix: go from row-major to column-major

>>> let xss = (1:>2:>Nil):>(3:>4:>Nil):>(5:>6:>Nil):>Nil
>>> xss
<<1,2>,<3,4>,<5,6>>
>>> transpose xss
<<1,3,5>,<2,4,6>>

interleave Source

Arguments

:: (KnownNat n, KnownNat d) 
=> SNat d

Interleave step, d

-> Vec (n * d) a 
-> Vec (d * n) a 

"interleave d xs" creates a vector:

<x_0,x_d,x_(2d),...,x_1,x_(d+1),x_(2d+1),...,x_(d-1),x_(2d-1),x_(3d-1)>
>>> let xs = 1 :> 2 :> 3 :> 4 :> 5 :> 6 :> 7 :> 8 :> 9 :> Nil
>>> interleave d3 xs
<1,4,7,2,5,8,3,6,9>

rotateLeft :: (Enum i, KnownNat n) => Vec n a -> i -> Vec n a Source

Dynamically rotate a Vector to the left:

>>> let xs = 1 :> 2 :> 3 :> 4 :> Nil
>>> rotateLeft xs 1
<2,3,4,1>
>>> rotateLeft xs 2
<3,4,1,2>
>>> rotateLeft xs (-1)
<4,1,2,3>

NB: use rotateLeftS if you want to rotate left by a static amount.

rotateRight :: (Enum i, KnownNat n) => Vec n a -> i -> Vec n a Source

Dynamically rotate a Vector to the right:

>>> let xs = 1 :> 2 :> 3 :> 4 :> Nil
>>> rotateRight xs 1
<4,1,2,3>
>>> rotateRight xs 2
<3,4,1,2>
>>> rotateRight xs (-1)
<2,3,4,1>

NB: use rotateRightS if you want to rotate right by a static amount.

rotateLeftS :: KnownNat n => Vec n a -> SNat d -> Vec n a Source

Statically rotate a Vector to the left:

>>> let xs = 1 :> 2 :> 3 :> 4 :> Nil
>>> rotateLeftS xs d1
<2,3,4,1>

NB: use rotateLeft if you want to rotate left by a dynamic amount.

rotateRightS :: KnownNat n => Vec n a -> SNat d -> Vec n a Source

Statically rotate a Vector to the right:

>>> let xs = 1 :> 2 :> 3 :> 4 :> Nil
>>> rotateRightS xs d1
<4,1,2,3>

NB: use rotateRight if you want to rotate right by a dynamic amount.

Element-wise operations

Mapping

map :: (a -> b) -> Vec n a -> Vec n b Source

"map f xs" is the vector obtained by applying f to each element of xs, i.e.,

map f (x1 :> x2 :>  ... :> xn :> Nil) == (f x1 :> f x2 :> ... :> f xn :> Nil)

and corresponds to the following circuit layout:

imap :: forall n a b. KnownNat n => (Index n -> a -> b) -> Vec n a -> Vec n b Source

Apply a function of every element of a vector and its index.

>>> :t imap (+) (2 :> 2 :> 2 :> 2 :> Nil)
imap (+) (2 :> 2 :> 2 :> 2 :> Nil) :: Vec 4 (Index 4)
>>> imap (+) (2 :> 2 :> 2 :> 2 :> Nil)
<2,3,*** Exception: CLaSH.Sized.Index: result 4 is out of bounds: [0..3]
>>> imap (\i a -> fromIntegral i + a) (2 :> 2 :> 2 :> 2 :> Nil) :: Vec 4 (Unsigned 8)
<2,3,4,5>

"imap f xs" corresponds to the following circuit layout:

smap :: KnownNat k => (forall l. SNat ((k - 1) - l) -> a -> b) -> Vec k a -> Vec k b Source

Apply a function to every element of a vector and the element's position (as an SNat value) in the vector.

>>> let rotateMatrix = smap (flip rotateRightS)
>>> let xss = (1:>2:>3:>Nil):>(1:>2:>3:>Nil):>(1:>2:>3:>Nil):>Nil
>>> xss
<<1,2,3>,<1,2,3>,<1,2,3>>
>>> rotateMatrix xss
<<1,2,3>,<3,1,2>,<2,3,1>>

Zipping

zipWith :: (a -> b -> c) -> Vec n a -> Vec n b -> Vec n c Source

zipWith generalises zip by zipping with the function given as the first argument, instead of a tupling function. For example, "zipWith (+)" applied to two vectors produces the vector of corresponding sums.

zipWith f (x1 :> x2 :> ... xn :> Nil) (y1 :> y2 :> ... :> yn :> Nil) == (f x1 y1 :> f x2 y2 :> ... :> f xn yn :> Nil)

"zipWith f xs ys" corresponds to the following circuit layout:

NB: zipWith is strict in its second argument, and lazy in its third. This matters when zipWith is used in a recursive setting. See lazyV for more information.

zipWith3 :: (a -> b -> c -> d) -> Vec n a -> Vec n b -> Vec n c -> Vec n d Source

zipWith3 generalises zip3 by zipping with the function given as the first argument, instead of a tupling function.

zipWith3 f (x1 :> x2 :> ... xn :> Nil) (y1 :> y2 :> ... :> yn :> Nil) (z1 :> z2 :> ... :> zn :> Nil) == (f x1 y1 z1 :> f x2 y2 z2 :> ... :> f xn yn zn :> Nil)

"zipWith3 f xs ys zs" corresponds to the following circuit layout:

NB: zipWith3 is strict in its second argument, and lazy in its third and fourth. This matters when zipWith3 is used in a recursive setting. See lazyV for more information.

zip :: Vec n a -> Vec n b -> Vec n (a, b) Source

zip takes two vectors and returns a vector of corresponding pairs.

>>> zip (1:>2:>3:>4:>Nil) (4:>3:>2:>1:>Nil)
<(1,4),(2,3),(3,2),(4,1)>

zip3 :: Vec n a -> Vec n b -> Vec n c -> Vec n (a, b, c) Source

zip takes three vectors and returns a vector of corresponding triplets.

>>> zip3 (1:>2:>3:>4:>Nil) (4:>3:>2:>1:>Nil) (5:>6:>7:>8:>Nil)
<(1,4,5),(2,3,6),(3,2,7),(4,1,8)>

izipWith :: KnownNat n => (Index n -> a -> b -> c) -> Vec n a -> Vec n b -> Vec n c Source

Zip two vectors with a functions that also takes the elements' indices.

>>> izipWith (\i a b -> i + a + b) (2 :> 2 :> Nil)  (3 :> 3:> Nil)
<*** Exception: CLaSH.Sized.Index: result 3 is out of bounds: [0..1]
>>> izipWith (\i a b -> fromIntegral i + a + b) (2 :> 2 :> Nil) (3 :> 3 :> Nil) :: Vec 2 (Unsigned 8)
<5,6>

"imap f xs" corresponds to the following circuit layout:

NB: izipWith is strict in its second argument, and lazy in its third. This matters when izipWith is used in a recursive setting. See lazyV for more information.

Unzipping

unzip :: Vec n (a, b) -> (Vec n a, Vec n b) Source

unzip transforms a vector of pairs into a vector of first components and a vector of second components.

>>> unzip ((1,4):>(2,3):>(3,2):>(4,1):>Nil)
(<1,2,3,4>,<4,3,2,1>)

unzip3 :: Vec n (a, b, c) -> (Vec n a, Vec n b, Vec n c) Source

unzip3 transforms a vector of triplets into a vector of first components, a vector of second components, and a vector of third components.

>>> unzip3 ((1,4,5):>(2,3,6):>(3,2,7):>(4,1,8):>Nil)
(<1,2,3,4>,<4,3,2,1>,<5,6,7,8>)

Folding

foldr :: (a -> b -> b) -> b -> Vec n a -> b Source

foldr, applied to a binary operator, a starting value (typically the right-identity of the operator), and a vector, reduces the vector using the binary operator, from right to left:

foldr f z (x1 :> ... :> xn1 :> xn :> Nil) == x1 `f` (... (xn1 `f` (xn `f` z))...)
foldr r z Nil                             == z
>>> foldr (/) 1 (5 :> 4 :> 3 :> 2 :> Nil)
1.875

"foldr f z xs" corresponds to the following circuit layout:

NB: "foldr f z xs" produces a linear structure, which has a depth, or delay, of O(length xs). Use fold if your binary operator f is associative, as "fold f xs" produces a structure with a depth of O(log_2(length xs)).

foldl :: (b -> a -> b) -> b -> Vec n a -> b Source

foldl, applied to a binary operator, a starting value (typically the left-identity of the operator), and a vector, reduces the vector using the binary operator, from left to right:

foldl f z (x1 :> x2 :> ... :> xn :> Nil) == (...((z `f` x1) `f` x2) `f`...) `f` xn
foldl f z Nil                            == z
>>> foldl (/) 1 (5 :> 4 :> 3 :> 2 :> Nil)
8.333333333333333e-3

"foldl f z xs" corresponds to the following circuit layout:

NB: "foldl f z xs" produces a linear structure, which has a depth, or delay, of O(length xs). Use fold if your binary operator f is associative, as "fold f xs" produces a structure with a depth of O(log_2(length xs)).

foldr1 :: (a -> a -> a) -> Vec (n + 1) a -> a Source

foldr1 is a variant of foldr that has no starting value argument, and thus must be applied to non-empty vectors.

foldr1 f (x1 :> ... :> xn2 :> xn1 :> xn :> Nil) == x1 `f` (... (xn2 `f` (xn1 `f` xn))...)
foldr1 f (x1 :> Nil)                            == x1
foldr1 f Nil                                    == TYPE ERROR
>>> foldr1 (/) (5 :> 4 :> 3 :> 2 :> 1 :> Nil)
1.875

"foldr1 f xs" corresponds to the following circuit layout:

NB: "foldr1 f z xs" produces a linear structure, which has a depth, or delay, of O(length xs). Use fold if your binary operator f is associative, as "fold f xs" produces a structure with a depth of O(log_2(length xs)).

foldl1 :: (a -> a -> a) -> Vec (n + 1) a -> a Source

foldl1 is a variant of foldl that has no starting value argument, and thus must be applied to non-empty vectors.

foldl1 f (x1 :> x2 :> x3 :> ... :> xn :> Nil) == (...((x1 `f` x2) `f` x3) `f`...) `f` xn
foldl1 f (x1 :> Nil)                          == x1
foldl1 f Nil                                  == TYPE ERROR
>>> foldl1 (/) (1 :> 5 :> 4 :> 3 :> 2 :> Nil)
8.333333333333333e-3

"foldl1 f xs" corresponds to the following circuit layout:

NB: "foldl1 f z xs" produces a linear structure, which has a depth, or delay, of O(length xs). Use fold if your binary operator f is associative, as "fold f xs" produces a structure with a depth of O(log_2(length xs)).

fold :: (a -> a -> a) -> Vec (n + 1) a -> a Source

fold is a variant of foldr1 and foldl1, but instead of reducing from right to left, or left to right, it reduces a vector using a tree-like structure. The depth, or delay, of the structure produced by "fold f xs", is hence O(log_2(length xs)), and not O(length xs).

NB: The binary operator "f" in "fold f xs" must be associative.

fold f (x1 :> x2 :> ... :> xn1 :> xn :> Nil) == ((x1 `f` x2) `f` ...) `f` (... `f` (xn1 `f` xn))
fold f (x1 :> Nil)                           == x1
fold f Nil                                   == TYPE ERROR
>>> fold (+) (5 :> 4 :> 3 :> 2 :> 1 :> Nil)
15

"fold f xs" corresponds to the following circuit layout:

ifoldr :: KnownNat n => (Index n -> a -> b -> b) -> b -> Vec n a -> b Source

Right fold (function applied to each element and its index)

>>> let findLeftmost x xs = ifoldr (\i a b -> if a == x then Just i else b) Nothing xs
>>> findLeftmost 3 (1:>3:>2:>4:>3:>5:>6:>Nil)
Just 1
>>> findLeftmost 8 (1:>3:>2:>4:>3:>5:>6:>Nil)
Nothing

"ifoldr f z xs" corresponds to the following circuit layout:

ifoldl :: KnownNat n => (a -> Index n -> b -> a) -> a -> Vec n b -> a Source

Left fold (function applied to each element and its index)

>>> let findRightmost x xs = ifoldl (\a i b -> if b == x then Just i else a) Nothing xs
>>> findRightmost 3 (1:>3:>2:>4:>3:>5:>6:>Nil)
Just 4
>>> findRightmost 8 (1:>3:>2:>4:>3:>5:>6:>Nil)
Nothing

"ifoldl f z xs" corresponds to the following circuit layout:

Specialised folds

dfold Source

Arguments

:: KnownNat k 
=> Proxy (p :: TyFun Nat * -> *)

The motive

-> (forall l. SNat l -> a -> (p $ l) -> p $ (l + 1))

Function to fold

-> (p $ 0)

Initial element

-> Vec k a

Vector to fold over

-> p $ k 

A dependently typed fold.

Using lists, we can define append (++) using foldr:

>>> import qualified Prelude
>>> let append xs ys = Prelude.foldr (:) ys xs
>>> append [1,2] [3,4]
[1,2,3,4]

However, when we try to do the same for Vec:

append' xs ys = foldr (:>) ys xs

We get a type error

>>> let append' xs ys = foldr (:>) ys xs

<interactive>:...
    Occurs check: cannot construct the infinite type: ... ~ ... + 1
    Expected type: a -> Vec ... a -> Vec ... a
      Actual type: a -> Vec ... a -> Vec (... + 1) a
    Relevant bindings include
      ys :: Vec ... a (bound at ...)
      append' :: Vec n a -> Vec ... a -> Vec ... a
        (bound at ...)
    In the first argument of ‘foldr’, namely ‘(:>)’
    In the expression: foldr (:>) ys xs

The reason is that the type of foldr is:

>>> :t foldr
foldr :: (a -> b -> b) -> b -> Vec n a -> b

While the type of (:>) is:

>>> :t (:>)
(:>) :: a -> Vec n a -> Vec (n + 1) a

We thus need a fold function that can handle the growing vector type: dfold. Compared to foldr, dfold takes an extra parameter, called the motive, that allows the folded function to have an argument and result type that depends on the current index into the vector. Using dfold, we can now correctly define (++):

import Data.Singletons.Prelude
import Data.Proxy

data Append (m :: Nat) (a :: *) (f :: TyFun Nat *) :: *
type instance Apply (Append m a) l = Vec (l + m) a

append' xs ys = dfold (Proxy :: Proxy (Append m a)) (const (:>)) ys xs

We now see that append' has the appropriate type:

>>> :t append'
append' :: KnownNat k => Vec k a -> Vec m a -> Vec (k + m) a

And that it works:

>>> append' (1 :> 2 :> Nil) (3 :> 4 :> Nil)
<1,2,3,4>

vfold :: KnownNat k => (forall l. a -> Vec l b -> Vec (l + 1) b) -> Vec k a -> Vec k b Source

Specialised version of dfold that builds a triangular computational structure.

Example:

compareSwap a b = if a > b then (a,b) else (b,a)
insert y xs     = let (y',xs') = mapAccumL compareSwap y xs in xs' :< y'
insertionSort   = vfold insert

Builds a triangular structure of compare and swaps to sort a row.

>>> insertionSort (7 :> 3 :> 9 :> 1 :> Nil)
<1,3,7,9>

The circuit layout of insertionSort, build using vfold, is:

Prefix sums (scans)

scanl :: (b -> a -> b) -> b -> Vec n a -> Vec (n + 1) b Source

scanl is similar to foldl, but returns a vector of successive reduced values from the left:

scanl f z (x1 :> x2 :> ... :> Nil) == z :> (z `f` x1) :> ((z `f` x1) `f` x2) :> ... :> Nil
>>> scanl (+) 0 (5 :> 4 :> 3 :> 2 :> Nil)
<0,5,9,12,14>

"scanl f z xs" corresponds to the following circuit layout:

NB:

last (scanl f z xs) == foldl f z xs

scanr :: (a -> b -> b) -> b -> Vec n a -> Vec (n + 1) b Source

scanr is similar to foldr, but returns a vector of successive reduced values from the right:

scanr f z (... :> xn1 :> xn :> Nil) == ... :> (xn1 `f` (xn `f` z)) :> (xn `f` z) :> z :> Nil
>>> scanr (+) 0 (5 :> 4 :> 3 :> 2 :> Nil)
<14,9,5,2,0>

"scanr f z xs" corresponds to the following circuit layout:

NB:

head (scanr f z xs) == foldr f z xs

postscanl :: (b -> a -> b) -> b -> Vec n a -> Vec n b Source

postscanl is a variant of scanl where the first result is dropped:

postscanl f z (x1 :> x2 :> ... :> Nil) == (z `f` x1) :> ((z `f` x1) `f` x2) :> ... :> Nil
>>> postscanl (+) 0 (5 :> 4 :> 3 :> 2 :> Nil)
<5,9,12,14>

"postscanl f z xs" corresponds to the following circuit layout:

postscanr :: (a -> b -> b) -> b -> Vec n a -> Vec n b Source

postscanr is a variant of scanr that where the last result is dropped:

postscanr f z (... :> xn1 :> xn :> Nil) == ... :> (xn1 `f` (xn `f` z)) :> (xn `f` z) :> Nil
>>> postscanr (+) 0 (5 :> 4 :> 3 :> 2 :> Nil)
<14,9,5,2>

"postscanr f z xs" corresponds to the following circuit layout:

mapAccumL :: (acc -> x -> (acc, y)) -> acc -> Vec n x -> (acc, Vec n y) Source

The mapAccumL function behaves like a combination of map and foldl; it applies a function to each element of a vector, passing an accumulating parameter from left to right, and returning a final value of this accumulator together with the new vector.

>>> mapAccumL (\acc x -> (acc + x,acc + 1)) 0 (1 :> 2 :> 3 :> 4 :> Nil)
(10,<1,2,4,7>)

"mapAccumL f acc xs" corresponds to the following circuit layout:

mapAccumR :: (acc -> x -> (acc, y)) -> acc -> Vec n x -> (acc, Vec n y) Source

The mapAccumR function behaves like a combination of map and foldr; it applies a function to each element of a vector, passing an accumulating parameter from right to left, and returning a final value of this accumulator together with the new vector.

>>> mapAccumR (\acc x -> (acc + x,acc + 1)) 0 (1 :> 2 :> 3 :> 4 :> Nil)
(10,<10,8,5,1>)

"mapAccumR f acc xs" corresponds to the following circuit layout:

Stencil computations

stencil1d Source

Arguments

:: KnownNat (n + 1) 
=> SNat (stX + 1)

Windows length stX, at least size 1

-> (Vec (stX + 1) a -> b)

The stencil (function)

-> Vec ((stX + n) + 1) a 
-> Vec (n + 1) b 

1-dimensional stencil computations

"stencil1d stX f xs", where xs has stX + n elements, applies the stencil computation f on: n + 1 overlapping (1D) windows of length stX, drawn from xs. The resulting vector has n + 1 elements.

>>> let xs = (1:>2:>3:>4:>5:>6:>Nil)
>>> :t xs
xs :: Num a => Vec 6 a
>>> :t stencil1d d2 sum xs
stencil1d d2 sum xs :: Num b => Vec 5 b
>>> stencil1d d2 sum xs
<3,5,7,9,11>

stencil2d Source

Arguments

:: (KnownNat (n + 1), KnownNat (m + 1)) 
=> SNat (stY + 1)

Window hight stY, at least size 1

-> SNat (stX + 1)

Window width stX, at least size 1

-> (Vec (stY + 1) (Vec (stX + 1) a) -> b)

The stencil (function)

-> Vec ((stY + m) + 1) (Vec ((stX + n) + 1) a) 
-> Vec (m + 1) (Vec (n + 1) b) 

2-dimensional stencil computations

"stencil2d stY stX f xss", where xss is a matrix of stY + m rows of stX + n elements, applies the stencil computation f on: (m + 1) * (n + 1) overlapping (2D) windows of stY rows of stX elements, drawn from xss. The result matrix has m + 1 rows of n + 1 elements.

>>> let xss = ((1:>2:>3:>4:>Nil):>(5:>6:>7:>8:>Nil):>(9:>10:>11:>12:>Nil):>(13:>14:>15:>16:>Nil):>Nil)
>>> :t xss
xss :: Num a => Vec 4 (Vec 4 a)
>>> :t stencil2d d2 d2 (sum . map sum) xss
stencil2d d2 d2 (sum . map sum) xss :: Num a => Vec 3 (Vec 3 a)
>>> stencil2d d2 d2 (sum . map sum) xss
<<14,18,22>,<30,34,38>,<46,50,54>>

windows1d Source

Arguments

:: KnownNat (n + 1) 
=> SNat (stX + 1)

Length of the window, at least size 1

-> Vec ((stX + n) + 1) a 
-> Vec (n + 1) (Vec (stX + 1) a) 

"windows1d stX xs", where the vector xs has stX + n elements, returns a vector of n + 1 overlapping (1D) windows of xs of length stX.

>>> let xs = (1:>2:>3:>4:>5:>6:>Nil)
>>> :t xs
xs :: Num a => Vec 6 a
>>> :t windows1d d2 xs
windows1d d2 xs :: Num a => Vec 5 (Vec 2 a)
>>> windows1d d2 xs
<<1,2>,<2,3>,<3,4>,<4,5>,<5,6>>

windows2d Source

Arguments

:: (KnownNat (n + 1), KnownNat (m + 1)) 
=> SNat (stY + 1)

Window hight stY, at least size 1

-> SNat (stX + 1)

Window width stX, at least size 1

-> Vec ((stY + m) + 1) (Vec ((stX + n) + 1) a) 
-> Vec (m + 1) (Vec (n + 1) (Vec (stY + 1) (Vec (stX + 1) a))) 

"windows2d stY stX xss", where matrix xss has stY + m rows of stX + n, returns a matrix of m+1 rows of n+1 elements. The elements of this new matrix are the overlapping (2D) windows of xss, where every window has stY rows of stX elements.

>>> let xss = ((1:>2:>3:>4:>Nil):>(5:>6:>7:>8:>Nil):>(9:>10:>11:>12:>Nil):>(13:>14:>15:>16:>Nil):>Nil)
>>> :t xss
xss :: Num a => Vec 4 (Vec 4 a)
>>> :t windows2d d2 d2 xss
windows2d d2 d2 xss :: Num a => Vec 3 (Vec 3 (Vec 2 (Vec 2 a)))
>>> windows2d d2 d2 xss
<<<<1,2>,<5,6>>,<<2,3>,<6,7>>,<<3,4>,<7,8>>>,<<<5,6>,<9,10>>,<<6,7>,<10,11>>,<<7,8>,<11,12>>>,<<<9,10>,<13,14>>,<<10,11>,<14,15>>,<<11,12>,<15,16>>>>

Conversions

toList :: Vec n a -> [a] Source

Convert a vector to a list.

>>> toList (1:>2:>3:>Nil)
[1,2,3]

bv2v :: KnownNat n => BitVector n -> Vec n Bit Source

Convert a BitVector to a Vec of Bits.

>>> let x = 6 :: BitVector 8
>>> x
0000_0110
>>> bv2v x
<0,0,0,0,0,1,1,0>

v2bv :: KnownNat n => Vec n Bit -> BitVector n Source

Convert a Vec of Bits to a BitVector.

>>> let x = (0:>0:>0:>1:>0:>0:>1:>0:>Nil) :: Vec 8 Bit
>>> x
<0,0,0,1,0,0,1,0>
>>> v2bv x
0001_0010

Misc

lazyV :: KnownNat n => Vec n a -> Vec n a Source

What you should use when your vector functions are too strict in their arguments.

For example:

-- Bubble sort for 1 iteration
sortV xs = map fst sorted :< (snd (last sorted))
 where
   lefts  = head xs :> map snd (init sorted)
   rights = tail xs
   sorted = zipWith compareSwapL lefts rights

-- Compare and swap
compareSwapL a b = if a < b then (a,b)
                            else (b,a)

Will not terminate because zipWith is too strict in its second argument:

>>> sortV (4 :> 1 :> 2 :> 3 :> Nil)
<*** Exception: <<loop>>

In this case, adding lazyV on zipWiths second argument:

sortVL xs = map fst sorted :< (snd (last sorted))
 where
   lefts  = head xs :> map snd (init sorted)
   rights = tail xs
   sorted = zipWith compareSwapL (lazyV lefts) rights

Results in a successful computation:

>>> sortVL (4 :> 1 :> 2 :> 3 :> Nil)
<1,2,3,4>

NB: There is also a solution using flip, but it slightly obfuscates the meaning of the code:

sortV_flip xs = map fst sorted :< (snd (last sorted))
 where
   lefts  = head xs :> map snd (init sorted)
   rights = tail xs
   sorted = zipWith (flip compareSwapL) rights lefts
>>> sortV_flip (4 :> 1 :> 2 :> 3 :> Nil)
<1,2,3,4>

data VCons a f :: * Source

To be used as the motive p for dfold, when the f in "dfold p f" is a variation on (:>), e.g.:

map' :: KnownNat k => (a -> b) -> Vec n a -> Vec n b
map' f = dfold (Proxy :: Proxy (VCons a)) (_ x xs -> f x :> xs)

Instances

type Apply * Nat (VCons a) l = Vec l a Source 

asNatProxy :: Vec n a -> Proxy n Source

Vector as a Proxy for Nat

Primitives

Traversable instance

traverse# :: Applicative f => (a -> f b) -> Vec n a -> f (Vec n b) Source

BitPack instance