| Safe Haskell | None |
|---|---|
| Language | Haskell98 |
Proof.Propositional.Empty
Documentation
withEmpty :: forall a b. (a -> Void) -> (Empty a => b) -> b Source #
Giving falsity witness by proving from Voida.
See also withEmpty'.
Since 0.4.0.0
withEmpty' :: forall a b. (forall c. a -> c) -> (Empty a => b) -> b Source #
Giving falsity witness by showing a entails everything.
See also withEmpty.
Since 0.4.0.0