| Safe Haskell | None |
|---|---|
| Language | Haskell2010 |
Data.CircularSeq
Synopsis
- data CSeq a
- cseq :: Seq a -> a -> Seq a -> CSeq a
- singleton :: a -> CSeq a
- fromNonEmpty :: NonEmpty a -> CSeq a
- fromList :: [a] -> CSeq a
- focus :: CSeq a -> a
- index :: CSeq a -> Int -> a
- adjust :: (a -> a) -> Int -> CSeq a -> CSeq a
- item :: Int -> Lens' (CSeq a) a
- rotateL :: CSeq a -> CSeq a
- rotateR :: CSeq a -> CSeq a
- rotateNL :: Int -> CSeq a -> CSeq a
- rotateNR :: Int -> CSeq a -> CSeq a
- rightElements :: CSeq a -> Seq a
- leftElements :: CSeq a -> Seq a
- asSeq :: CSeq a -> Seq a
- reverseDirection :: CSeq a -> CSeq a
- allRotations :: CSeq a -> CSeq (CSeq a)
- findRotateTo :: (a -> Bool) -> CSeq a -> Maybe (CSeq a)
- rotateTo :: Eq a => a -> CSeq a -> Maybe (CSeq a)
- zipLWith :: (a -> b -> c) -> CSeq a -> CSeq b -> CSeq c
- zipL :: CSeq a -> CSeq b -> CSeq (a, b)
- zip3LWith :: (a -> b -> c -> d) -> CSeq a -> CSeq b -> CSeq c -> CSeq d
- insertOrd :: Ord a => a -> CSeq a -> CSeq a
- insertOrdBy :: (a -> a -> Ordering) -> a -> CSeq a -> CSeq a
- isShiftOf :: Eq a => CSeq a -> CSeq a -> Bool
Documentation
Nonempty circular sequence
Instances
fromNonEmpty :: NonEmpty a -> CSeq a Source #
builds a CSeq
index :: CSeq a -> Int -> a Source #
Access the i^th item (w.r.t the focus) in the CSeq (indices modulo n).
running time: \(O(\log (i \mod n))\)
>>>index (fromList [0..5]) 11>>>index (fromList [0..5]) 22>>>index (fromList [0..5]) 55>>>index (fromList [0..5]) 104>>>index (fromList [0..5]) 60>>>index (fromList [0..5]) (-1)5>>>index (fromList [0..5]) (-6)0
adjust :: (a -> a) -> Int -> CSeq a -> CSeq a Source #
Adjusts the i^th element w.r.t the focus in the CSeq
running time: \(O(\log (i \mod n))\)
>>>adjust (const 1000) 2 (fromList [0..5])CSeq [0,1,1000,3,4,5]
rotateL :: CSeq a -> CSeq a Source #
rotates the focus to the left
running time: O(1) (amortized)
>>>rotateL $ fromList [3,4,5,1,2]CSeq [2,3,4,5,1]>>>mapM_ print . take 5 $ iterate rotateL $ fromList [1..5]CSeq [1,2,3,4,5] CSeq [5,1,2,3,4] CSeq [4,5,1,2,3] CSeq [3,4,5,1,2] CSeq [2,3,4,5,1]
rotateR :: CSeq a -> CSeq a Source #
rotates one to the right
running time: O(1) (amortized)
>>>rotateR $ fromList [3,4,5,1,2]CSeq [4,5,1,2,3]
rotateNL :: Int -> CSeq a -> CSeq a Source #
Rotates i elements to the left.
pre: 0 <= i < n
running time: \(O(\log i)\) amoritzed
>>>rotateNL 0 $ fromList [1..5]CSeq [1,2,3,4,5]>>>rotateNL 1 $ fromList [1..5]CSeq [5,1,2,3,4]>>>rotateNL 2 $ fromList [1..5]CSeq [4,5,1,2,3]>>>rotateNL 3 $ fromList [1..5]CSeq [3,4,5,1,2]>>>rotateNL 4 $ fromList [1..5]CSeq [2,3,4,5,1]
rotateNR :: Int -> CSeq a -> CSeq a Source #
Rotates i elements to the right.
pre: 0 <= i < n
running time: \(O(\log i)\) amortized
>>>rotateNR 0 $ fromList [1..5]CSeq [1,2,3,4,5]>>>rotateNR 1 $ fromList [1..5]CSeq [2,3,4,5,1]>>>rotateNR 4 $ fromList [1..5]CSeq [5,1,2,3,4]
rightElements :: CSeq a -> Seq a Source #
All elements, starting with the focus, going to the right
leftElements :: CSeq a -> Seq a Source #
All elements, starting with the focus, going to the left
>>>leftElements $ fromList [3,4,5,1,2]fromList [3,2,1,5,4]
reverseDirection :: CSeq a -> CSeq a Source #
Reversres the direction of the CSeq
running time: \(O(n)\)
>>>reverseDirection $ fromList [1..5]CSeq [1,5,4,3,2]
allRotations :: CSeq a -> CSeq (CSeq a) Source #
All rotations, the input CSeq is the focus.
>>>mapM_ print . allRotations $ fromList [1..5]CSeq [1,2,3,4,5] CSeq [2,3,4,5,1] CSeq [3,4,5,1,2] CSeq [4,5,1,2,3] CSeq [5,1,2,3,4]
findRotateTo :: (a -> Bool) -> CSeq a -> Maybe (CSeq a) Source #
Finds an element in the CSeq
>>>findRotateTo (== 3) $ fromList [1..5]Just (CSeq [3,4,5,1,2])>>>findRotateTo (== 7) $ fromList [1..5]Nothing
zipLWith :: (a -> b -> c) -> CSeq a -> CSeq b -> CSeq c Source #
"Left zip": zip the two CLists, pairing up every element in the *left* list with its corresponding element in the right list. If there are more items in the right clist they are discarded.
zip3LWith :: (a -> b -> c -> d) -> CSeq a -> CSeq b -> CSeq c -> CSeq d Source #
same as zipLWith but with three items
insertOrd :: Ord a => a -> CSeq a -> CSeq a Source #
Given a circular seq, whose elements are in increasing order, insert the new element into the Circular seq in its sorted order.
>>>insertOrd 1 $ fromList [2]CSeq [2,1]>>>insertOrd 2 $ fromList [1,3]CSeq [1,2,3]>>>insertOrd 31 ordListCSeq [5,6,10,20,30,31,1,2,3]>>>insertOrd 1 ordListCSeq [5,6,10,20,30,1,1,2,3]>>>insertOrd 4 ordListCSeq [5,6,10,20,30,1,2,3,4]>>>insertOrd 11 ordListCSeq [5,6,10,11,20,30,1,2,3]
running time: \(O(n)\)