Vgrep.Parser

Parsing grep output

parseGrepOutput :: [Text] -> [FileLineReference]

Parses lines of Text, skipping lines that are not valid grep output.

parseLine :: Text -> Maybe FileLineReference

Parses a line of grep output. Returns Nothing if the line cannot be parsed.

The output should consist of a file name, line number and the content, separated by colons:

>>> parseLine "path/to/file:123:foobar"
Just (FileLineReference {getFile = File {getFileName = "path/to/file"}, getLineReference = LineReference {getLineNumber = Just 123, getLineText = "foobar"}})

Omitting the line number still produces valid output:

>>> parseLine "path/to/file:foobar"
Just (FileLineReference {getFile = File {getFileName = "path/to/file"}, getLineReference = LineReference {getLineNumber = Nothing, getLineText = "foobar"}})

However, an file name must be present:

>>> parseLine "foobar"
Nothing

Re-export

data FileLineReference

Instances

Eq FileLineReference

Methods

(==) :: FileLineReference -> FileLineReference -> Bool

(/=) :: FileLineReference -> FileLineReference -> Bool

Show FileLineReference

Methods

showsPrec :: Int -> FileLineReference -> ShowS

show :: FileLineReference -> String

showList :: [FileLineReference] -> ShowS